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en:hydro:greenampt [2017/10/24 22:25] ckuellsen:hydro:greenampt [2024/04/10 10:02] (current) – external edit 127.0.0.1
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 stated as follows: stated as follows:
  
-$$ +$$q = \frac{dI}{dt} = -K_s * \left[\frac{h_f-(h_s+Z)}{Z}\right]$$
-\begin{equation*} +
-q = \frac{dI}{dt} = -K_s * \left[\frac{h_f-(h_s+Z)}{Z}\right] +
-\end{equation*} +
-$$+
  
 where $K_s$ is the hydraulic conductivity and $I(t)$ is the cumulative infiltration at time $t$ that is equal to $Z*(\theta_s - \theta_0)$ (conservation of mass).  where $K_s$ is the hydraulic conductivity and $I(t)$ is the cumulative infiltration at time $t$ that is equal to $Z*(\theta_s - \theta_0)$ (conservation of mass). 
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 Using the above relation for $I(t)$ to eliminate $Z$ and performing the integration yields, Using the above relation for $I(t)$ to eliminate $Z$ and performing the integration yields,
  
-$$ +$$I = K_s*t-(h_f-h_s)*(\theta_s - \theta_0)* log_e \left( 1 - \frac{I}{(h_f-h_s)*(\theta_s-\theta_0)}\right)$$
-\begin{equation*} +
-I = K_s*t-(h_f-h_s)*(\theta_s - \theta_0)* log_e \left( 1 - \frac{I}{(h_f-h_s)*(\theta_s-\theta_0)}\right) +
-\end{equation*} +
-$$ +
- +
-$$ +
-\begin{table} +
-  \centering +
-  \begin{tabular}{ l l l l } +
-with &   $I(t)$ & infiltration amount & $[cm]$   \\ +
-     &   $K_s$  & hydr. conductivity  & $[cm/h]$  \\ +
-     &   $h_f$  & wetting front pressure head (negative) & $cm$  \\ +
-     &   $h_s$  & water pressure at surface (ponding)    & $cm$  \\ +
-     &   $\theta_s$ & moisture content at saturation     & $-$   \\ +
-     &   $\theta_0$ & antecedent moisture                & $-$   \\ +
-\end{tabular} +
-\end{table} +
-$$+
  
 +with $I(t)$ infiltration amount in [cm], $K_s$ hydr. conductivity in [cm/h], $h_f$ wetting front pressure head (negative) in [cm], $h_s$  water pressure at surface (ponding) in cm, $\theta_s$ moisture content at saturation, $\theta_0$ antecedent moisture.
  
 In order to solve this implicit equation, we need to bring $I(t)$ to one side of the equation:  In order to solve this implicit equation, we need to bring $I(t)$ to one side of the equation: 
  
-$$ +$$\frac{1}{K_s}*\left[I -(h_f-h_s)*(\theta_s - \theta_0)* log_e \left( 1 - \frac{I}{(h_f-h_s)*(\theta_s-\theta_0)}\right)\right] = t $$
-\begin{equation*} +
-\frac{1}{K_s}*\left[I -(h_f-h_s)*(\theta_s - \theta_0)* log_e \left( 1 - \frac{I}{(h_f-h_s)*(\theta_s-\theta_0)}\right)\right] = t +
-\end{equation*} +
-$$+
  
 We can then insert $I$ can calculate $t$ - we calculate the time that corresponds to a given infiltration amount. An R-code to calculate infiltration amounts with Green & Ampt looks like this: We can then insert $I$ can calculate $t$ - we calculate the time that corresponds to a given infiltration amount. An R-code to calculate infiltration amounts with Green & Ampt looks like this:
/usr/www/users/uhydro/doku/data/attic/en/hydro/greenampt.1508876758.txt.gz · Last modified: 2024/04/10 10:14 (external edit)